Question

Please help ASAP!!

Ten 6-sided dice are rolled. What is the probability that exactly three of the dice show a 1?

Answer 1

PLEASE HELP ASAP

Answer 2

hmm i'm not sure about this
my guess is to use combination 10 choose 3 multiply that by the probability of getting a 1 per one die

Answer 3

\(\Large \binom{10}{3}*(1/6)\) this how you write it

Answer 4

@SithsAndGiggles

Answer 5

@xapproachesinfinity that's almost right... We're dealing with two possible outcomes here - the outcome that we roll a particular number (in this case a 1) and the outcome that we DO NOT roll that number (any of 2,3,4,5,6). Hence we have a binomial distribution with \(p=\dfrac{1}{6}\) and \(n=10\).

The desired probability is given by
\[\binom{10}3\left(\frac{1}{6}\right)^{10−3}\left(\frac{5}{6}\right)^3\]

Answer 6

i see, you are right i didn't consider the outcome for not rolling a 1
now i understand it what i was missing
@SithsAndGiggles thanks