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Mathematics 15 Online
OpenStudy (anonymous):

How do you find terms in a sequence?

OpenStudy (anonymous):

OpenStudy (mathstudent55):

This sequence needs the previous two terms to determine a term. \(a_{n - 1} \) is the previous term, and \(a_{n - 2} \) is the term before the previous term.

OpenStudy (mathstudent55):

You are given the first two terms, \(a_1\) and \(a_2\). Use those terms to find the third term. Then use the second and third terms to find the fourth term, etc.

OpenStudy (solomonzelman):

do you experience any difficulty reading the notations in your question, like \(\large\color{black}{ b_3 }\) and all that stuff?

OpenStudy (anonymous):

It doesn't line up when I plug in the terms given :/

OpenStudy (mathstudent55):

\(\large b_n = -3b_{n - 2} + 5b_{n - 1} \) We want \(b_3\), so we use n = 3. That means \(b_{n - 2} = b_1\), and \(b_{n - 1} = b_2\).

OpenStudy (mathstudent55):

\(\large b_n = -3b_{n - 2} + 5b_{n - 1} \) \(\large \color{red} {b_1 = -1}\); \(\large \color{green}{b_2 = 6}\) \(\large \color{blue}{b_3} = -3\color{red}{b_1} + 5\color{green}{b_2} = -3\color{red}{(-1)} + 5\color{green}{(6)} = \color{blue}{33} \) \(\large b_4 = -3b_{4 - 2} + 5b_{4 - 1} = -3\color{green}{b_{2}} + 5\color{blue}{b_{3}} = \) etc.

OpenStudy (anonymous):

@mathstudent55 so my answer's A?

OpenStudy (mathstudent55):

Yes. Even without calculating b4 and b5, the answer must be A because choice A is the only one that has the correct b3 term.

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