Find the indicated limit, if it exists. limit of f of x as x approaches negative 8 where f of x equals x plus 9 when x is less than negative 8 and f of x equals negative seven minus x when x is greater than or equal to negative 8 -8 1 17 The limit does not exist.
i have no idea how to do this
let me interpret the question: Find \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~-8}f(x)}\) ? where, \(\LARGE\color{black}{ f(x) = \begin{cases} & x+9,~~~~~~~~~~{\large x<-8} \\ & -7-x,~~~~~~{\large x\ge-8} \end{cases} }\)
is this interpretation correct?
correct
so to find the left sided limit, you need to plug in -8, into x+9 and to find the right sided limit, you need to plug in -8, into -7-x.
if the two sides of the limit are no equivalent, then \(\large\color{black}{\displaystyle\lim_{x \rightarrow ~-8}f(x)~~DNE}\)
it equal;s 1
yup!
oh. so to find the limit, just plug in the numbers that they give you
basically, but you need to verify that \(\Large\color{blue}{\displaystyle\lim_{x \rightarrow ~-8^{-}}f(x)=\displaystyle\lim_{x \rightarrow ~-8^{+}}f(x)}\)
oh. right.
if, \(\Large\color{blue}{\displaystyle\lim_{x \rightarrow ~-8^{-}}f(x) \ne\displaystyle\lim_{x \rightarrow ~-8^{+}}f(x)}\) then \(\Large\color{blue}{\displaystyle\lim_{x \rightarrow ~-8}f(x)~~\color{black}{\rm DNE}}\)
i have a couple of more. do you mind?
in your case, as you have already said both parts are equal to 1:) so 1 is the answer you need
yes, sure.....
you can draw th piece wise functions and the limits, that would be faster for both of us:)
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