a 3-mile cab ride costs $5.75. A 5-mile cab ride costs $8.25. Part 1: Find a linear equation that models that costs c as a function of the distance d. (Create a table with data points and use the data from the table to write the equation) part 2: How much will a 10-mile cab ride costs (just need help showing work >.< I do mental math)
They give you 2 points in the information, you need to find the rate of change of miles vs cost
(x,y) = (3 , 5.75) (x1,y1) = (5, 8.25) Rte of change = (y - y1) / (x - x1)
Then use the equation point-slope form y - y1 = Rate of change*(x - x1) to get a equation for the line
hm... C= 1.25 + 2.00 or C = 1.25 d + 2 (cost of 10-mile ride = 14.50 I just need help with how to show work for my answer
the equation we find will be in the form y - y1 = m(x-x1) we need to first find m
using the two points from the equation, the ones i listed above m = (8.25 - 5.75)/ (5-3)
so, the slope m = 2.5/2 = 1.25
oh okay ..
now from the two points again, (3, 5.75) and (5,8.25) and the slope found m = 1.25 form and equation in the form y - y1 = m*(x-x1) Where x1 and y1 are from one of the points in the problem, either one is fine to use
oh I understand now c: thanks
what do you get
how you got 1.25 from the points
y - 5.75 = 1.25(x - 3) y - 5.75 = 1.25x - 3.75 y = 1.25x + 2 Let c = y = cost , and x = miles = d c(d) = 1.25*d + 2
1.25 is the rate of change of distance per mile , using the 2 points given (x,y) = (3 , 5.75) (x1,y1) = (5, 8.25) Rate of change = (y - y1) / (x - x1) = (8.25 - 5.75) / (5 - 3) = 1.25
Now that you have the equation of the cost per distance c(d) = 1.25d + 2 You can use that to find the cost of a 10 mile ride, Let d = 10 and find c(10) = ...
$14.50
yep, c(10 ) = 1.25*10 + 2 = 14.50
thanks so much c:
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