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Mathematics 22 Online
OpenStudy (eric_d):

Differentiate with respect to x.

OpenStudy (eric_d):

\[\cos^4(1-x)\]= \[4\cos^3(1-x).-\sin(1-x).-1\]

OpenStudy (eric_d):

\(= 4cos^3(1-x)sin(1-x)\)

OpenStudy (eric_d):

Is this arrangement correct ?

OpenStudy (solomonzelman):

yes, for the first reply

OpenStudy (solomonzelman):

yes for the second reply too

OpenStudy (solomonzelman):

your minus next to the sin and next to the 1, both have disappeared, became +

OpenStudy (solomonzelman):

when you use latex add \ before trigonometric functions and before log and ln.

OpenStudy (solomonzelman):

Like `\(\large\color{black}{ \cos^3(1-x) }\)` \(\large\color{black}{ \cos^3(1-x) }\) and not, `\(\large\color{black}{ cos^3(1-x) }\)` \(\large\color{black}{ cos^3(1-x) }\)

OpenStudy (eric_d):

Okay

OpenStudy (solomonzelman):

(I am assuming that your dots are multiplication)

OpenStudy (eric_d):

Yes,it is

OpenStudy (solomonzelman):

why don't you use the \times for multiplication sign?

OpenStudy (solomonzelman):

and just as far as the notations go, say: \(\large\color{red}{ 4 \cos^3(1-x) \times(-\sin(n-1))\times (-1) }\) \(\large\color{black}{ 4 \cos^3(1-x) \sin(n-1) }\) (correct in red)

OpenStudy (eric_d):

The final answer is also same as \(4~sin~(1-x)~cos^3~(1-x)\) rite

OpenStudy (solomonzelman):

yup

OpenStudy (eric_d):

Alrite!

OpenStudy (solomonzelman):

sure, but remember not to put two signs (multiplication and the minus) without any parenthesis separation, just for the sake of the notations. as far as the work goes, very very good job!

OpenStudy (eric_d):

Okay :) Thanks @SolomonZelman

OpenStudy (solomonzelman):

Yw

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