Is f(x) = 0.69(1.03)x a decreasing or increasing function?
All you need to do for this problem is graph the equation
ohh thanks
Desmos is a really good online grapher. If you graphed the equation you would see that the equation is increasing.
Also can you give me a medal?
all you have to do is click the best response button
there you go :)
Thanks!!
no need for graphing
oh wait by what percent?
\(\large\color{black}{ f(x) = 0.69(1.03)^x}\) when \(\large\color{black}{x=1}\), then you have: \(\large\color{black}{ 0.69 \times1.03}\) when \(\large\color{black}{x=2}\), then you have: \(\large\color{black}{ 0.69 \times 1.03 \times 1.03}\) when \(\large\color{black}{x=3}\), then you have: \(\large\color{black}{ 0.69 \times 1.03 \times 1.03 \times 1.03}\) when \(\large\color{black}{x=4}\), then you have: \(\large\color{black}{ 0.69 \times 1.03 \times 1.03 \times 1.03\times 1.03}\) and on
right?
yeah
so each time (as \(\large\color{black}{ x}\) increases by \(\large\color{black}{ 1}\) ) you multiply times \(\large\color{black}{ 1.03}\)
that means that the function is increasing.
because anytime, when you multiply a(ny) number \(\large\color{black}{ C}\) by a number greater than 1, then the result will be greater than this number \(\large\color{black}{ C}\) .
So for any exponential function \(\large\color{black}{ y=a(b)^x}\) (when \(\large\color{black}{ a}\) is positive) ~ when \(\large\color{black}{b>0}\) , the \(\large\color{black}{ f(x)}\) is increasing. ~ when \(\large\color{black}{b<0}\) , the \(\large\color{black}{ f(x)}\) is decreasing.
okay and by what percent is it increasing?
okay, you are multiplying times \(\large\color{black}{ 1.03}\) , which is same as taking \(\large\color{black}{ 103 \text{%}}\) (of the previous input) each time.
\(\large\color{black}{ 100 \text{%}}\) is what you had, and \(\large\color{black}{ +3 \text{%}}\) is the extra part.
ohh ok ok I get that was helpful thank you!
yw
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