Question

find the sum of the infinite series" 12-1+1/12-1/144+...

Answer 1

\[\frac{a}{1-r}\] for this one

Answer 2

hint, you're series involves powers of 12

Answer 3

evidently \(a=12\)

Answer 4

and \(r=?\)

Answer 5

is it clear what \(r\) is in this example?

Answer 6

1?

Answer 7

heck no

Answer 8

r is the ratio of one term to the previous term, not the second term

Answer 9

take any term and divide it by the previous one
it should really be obvious from your eyeballs, and not require a computation
what do you multiply 12 by to get -1?

Answer 10

negative 12 @satellite73

Answer 11

close but you are doing it backwards

Answer 12

\[12\times r=-1\]

Answer 13

\[r=?\]

Answer 14

is that even possible? @satellite73

Answer 15

i sure hope so because you are doing it an infinite number of times

Answer 16

all you have to do is write it
\[r=-\frac{1}{12}\]

Answer 17

12/(1 - (-1/12)) = 12/(13/12) = 144/13 = 11.076?? @satellite73

Answer 18

i would leave it at \(\frac{144}{13}\) looks a lot prettier
good job though