LET f(x) = x^4 + ax^2 + b . The graph of f has a relative maximum at (0,1) and and inflection point at x=1 . Find the values of a and b
In order to do that, we should calculate the derivatives of f(x) first
do you remember the power rule?
4x^3 + 2ax ?
yep
At a maximum value, the slope of a tangent will be zero, and the derivative is the slope of the tangent, set f '(x) = 0
k hold on
\[f ' (x) = 0 = 4x^2+ 2ax\] now calculate the second derivative
I set it to 0 and I am solving for what because I have a and x
8x + 2a
right, \[f ''(x) = 8x + 2a \] f ''(x) = 0 , when x = 1
the inflection point is where the second derivative = 0, the graph switches concavity
yeah so how do I find that , I make the second derrivative equal to 0?
exactly, f ''(1) = 0
so I plug 1 in for a ?
or x
no, the inflection point occurs when x = 1
we are trying to find a
but I have to find the values of a and b
yes, we use both equations, the first derivative, and the second, 2 equations, 2 unknowns a and b
ok so we found the derrivatives but what is the value of a and b?
actually, to get b, you can just use the regular function f(x) at point (0,1)
f(0) = 1 = 0 + a*0 + b b = 1
ok that was the normal equation but what about a ? do I use the first or second derivative
either one will be fine, since you are only finding one variable, i would go with the second derivative
look at all the ghosts
BOO!!!!
it must be North Korea
oh now they are going away bye bye ghosts
what are ghosts ? and I do not know how to get a
f '' (x) = 8x + 2a at x = 1 inflection f''(x) = 0 f ''(1) = 0 = 8(1) + 2a
is it 2?
oh
wait, we messed up the second derivative...the first function is to the 4th power
4x^3
f(x) = x^4 + ax^2 + b f ' (x) = 4x^3 + 2ax f '' (x) = 12x^2 + 2a
f ''(x) = 0 at x=1 inflection point f ''(1) = 12(1)^2 + 2a = 0 12 + 2a = 0
a = -6
thank you so much!
you understand what they want you to know? f ' (x) = 0 ...maximum/minimum values f '' (x) = 0 ...inflection points
yes
but from the function in this problem, when x=0 from the point (0,1) , you can find b from just f(x) by letting x=0
x = 0, f(0) = b
some probs, you might have to use the first derivative as a maximum or minimum to find thevariable, if the function doesnt simplify like that
alright , I got it (: thank you !!
anytime, pretty fun prob there
i would graph it, and use a slider for a and b, you can change a and b on the fly and see what the graph does
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