Integrate(2x^-5). How do you do this question?
is it \(\large\color{black}{\displaystyle\int\limits_{~}^{~}2x^{-5}dx}\) ?
yes
then you can take the constant out, like this: 2\(\large\color{black}{\displaystyle\int\limits_{~}^{~}x^{-5}dx}\) and apply the power rule.
\(\large\color{black}{2\displaystyle\int\limits_{~}^{~}x^{-5}dx=2\times \frac{\LARGE x^{-5\color{red}{+1}} }{\LARGE \color{red}{-5+1}}+C}\)
what do you get as your answer?
(2(x^-4)/(-4))
yes, right: \(\large\color{black}{ 2 \times \frac{\LARGE x^{-4} }{\LARGE -4} +C }\) but you can simplify this a bit more
-(x^-4/2)
yup, \(\large\color{black}{ \frac{\LARGE x^{-4} }{\LARGE -2} +C }\)
thank you..
or, \(\large\color{black}{ -\frac{\LARGE x^{-4} }{\LARGE 2} +C }\) same thing
what does your teacher require to to farther do, does (s)he want you to re-write using a positive exponent?
or would this result satisfy your teacher?
Yes this result works
okay, but make sure to include the +C :)
You\(\normalsize\color{blue}{ \rm ~welcome! }\)
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