Question

WILL MEDAL..write the first four terms of the geometeric sequence satisfying the following conditions: A2=11, and A3=-121

Answer 1

so you can find the common ratio by: \(\large\color{blue}{ r=a_3 \div a_2 }\)

(because for any arithmetic sequence, \(\large\color{black}{ r=a_{n} \div a_{n-1} }\))

Answer 2

After you find \(\large\color{black}{ r }\) you will have that:

~ \(\large\color{black}{ a_1= a_2\div r }\)
~ \(\large\color{black}{ a_2 }\) and \(\large\color{black}{ a_3 }\) are given
~ \(\large\color{black}{ a_4= a_3\times r }\)

there are the terms

Answer 3

I mean for any geometric sequence, in the first reply, in the parenthesis, excuse my mistake)

Answer 4

anything troubling you?

Answer 5

so it would b e 1,11,121, and 1331? @SolomonZelman

Answer 6

the first 3 yes, the fourth @SolomonZelman will have to determine.

Answer 7

you have the numbers but not the signs

Answer 8

it is -1, 11, -121, 1331