Question

Write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3).
y = 7x - 3

y = -1/7 x + 2

y = -7x + 10

y = 7x - 10

Answer 1

Can you tell what the slope of the given line is
y = 7x + 2
?

Answer 2

Slope intercept form of a line

y = m*x+b

m= slope and b= y-intercept

Answer 3

The slope of the give line ; y = 7x + 2; is 7.

A line parallel to that given line will have the SAME slope.

Slope of the parallel line also = 7

Answer 4

i dont really know how to do any of it

Answer 5

Have point (x1,y1) = (1,-3) and slope m = 7

Use Point-Slope form for a line to get line

y - y1 = m(x-x1)

plug in the values of m, x1, y1

Answer 6

so (x1,y1) = (1,-3) and slope m = 7?? idk

Answer 7

yes, just put those numbers into

y - y1 = m*(x - x1)

Answer 8

Summary. the slope of the line given is 7 , it is in the form y=m*x + b, m=7.

A parallel line will have the same slope.

Answer 9

y + 3 = 7(x - 1)

y + 3 = 7x - 7

y = 7x - 10

Answer 10

1-(-3)=m*7x + 2

Answer 11

y = 7x - 10

is parallel to

y = 7x + 2

Answer 12

m = 7, you have to replace m with 7, you still had m in your equation

Answer 13

first you find the slope of the given equation. It is 7.
now use y = mx + b form
slope(m) = 7
(1,-3)...x = 1 and y = -3
now we sub and find b (the y intercept)
-3 = 7(1) + b
-3 = 7 + b
-3 - 7 = b
-10 = b
so your parallel equation is : y = 7x - 10

Answer 14

ok thank you i still dont really get it but thanks

Answer 15

A slope is how 'steep' the ramp of the line is.

A parallel ramp will have the same 'steepness'