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A spherical balloon is filled with helium at the rate of 8 in^3/sex . How fast is the diameter of the balloon increasing when the volume of the ballon is 36p in ^3?
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id assume 4
how did you get that
relationship of 36 and 8
between*
4.5
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you need to apply the chain rule of calculus
how
What is the expression for the volume of a sphere?
4/3 pie r
r 3d
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r to the 3
4/3 pi r3
good, now express it in terms of the diameter instead of the radius
I am so confused
so 4/3 pi 2r3
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because the diam is twice as large as radius
so the diameter is 4/3 pi 2r3
yea
V = 4/3*pi*r^3 but r=d/2 Now substitute and simplify
ok but how fast is the diameter of the balloon increasing when the volume of the ballon is 36pi
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2/3
Can you solve for V in terms of d?
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