Question

When the expression mx^2 + 6x +n is divisible by x-3, find the value of 18m+2n-3

Answer 1

@jim_thompson5910 @ganeshie8

Answer 2

\(mx^2 + 6x +n\) is divisible by \((x-3)\)
hence
\(\large\tt \begin{align} \color{black}{f(3)=m(3)^2+6(3)+n=0}\end{align}\)

Answer 3

@mathmath333 continure

Answer 4

did u simplify that

Answer 5

\(\large\tt \begin{align} \color{black}{9m+n+18=0}\end{align}\)

Answer 6

try to multiply it by \(2\)

Answer 7

18m + 2n+36=0

Answer 8

so the final answer t the question is -39

Answer 9

\(\large\tt \begin{align} \color{black}{9m+n+18=0\\
9m
+n=-18\\18m+2n=-36\\18m+2n-3=-36-3=-39}\end{align}\)

Answer 10

thanks