law of sines a distance BC of 160m is laid off on one side of the rier. found that B=109.3 C=15.8. find AB round to nearest meter
Interesting name* Hah.
you or me?
You of course. Ok. analyzing this problem.
well, i didn't know what to call myself so it's a song lyric i like actually "ooooo sometimes i get this feeling, yeah" kind of a cool older tune
i thought it fit since math gives me a general funny feeling...all those unknowns (math joke)
I used the law of sines but i keep coming up short on the answer, i really don't know how i could be messing this up unless i am needing to make another triangle than the one given
what is a rier?
a river. sorry. slang for river maybe :)
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Just making a guess at what the triangle might be.
oh
54.9 for A
looks good, assuming he/she means angles B and C.. question is kinda ugly.. lol sorry
Law of sines: \[\frac{a}{\sin A} =\frac{c}{\sin C }\]
i have some xtra credito word problems that are really ugly. do not make sense what so ever.
Were you able to solve this one?
a/sin 54.9=160/sin109.3 .94a=(82)(160) a=140 140/sin54.9=c/sin15.8 (140)(.27)/.82 =.82c c=46 the answer is supposed to be 53 meters. My answers are no where near, I don't know what I have done incorrectly
a is already given.
Let's check.
i got 53.24
160/sin(180-15.8-109.3) = AB/sin(15.8)
\[\frac{160}{\sin(54.9)}=\frac{c}{\sin(15.8)}\]
\[160\sin(15.8) = c\sin(54.9)\]\[c=\frac{160\sin(15.8)}{\sin(54.9)} \approx 53.24\]
Rounding up to the nearest meter,you would have \(53~\text{meters}\)
ok I was brain farting bad. using sub.. ok thank you very much. cheers
No problem :)
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