Question

In order to solve the equation log x^2+2x=0, what line must be added to the graph of y=logx-1

Answer 1

A) y=-x B) y=-x-1 C) y=-x+1 D) y=2x-1 E) y=2x+1

Answer 2

@hartnn

Answer 3

@ganeshie8 @mathmath333

Answer 4

log (x^2+2x) - 0
?

Answer 5

not sure wat u mean

Answer 6

lol, whats the question ?

Answer 7

log (x^2+2x) = 0
?

Answer 8

no logx^2 + 2x outside

Answer 9

ok,
so
\(\log (x^2)+2x =0 \)

Answer 10

log x^n = n log x

Answer 11

I think that:
from \[\log (x ^{2})+2x=0,\]
I get:
\[\log (x)+x=0\]
and:
\[\log(x)-1+1+x=0\]
from which:
\[y+1+x=0\]

Answer 12

nevertheless the there is not the option 1+x

Answer 13

log x + x = 0
subtract log x -1 =0

you get x - (-1) = 0
x+1 = 0
yeah, i get y=x+1 too

or
y = -x-1
will also do

Answer 14

thanks both

Answer 15

thank you! @CrashOnce

Answer 16

welcome ^_^