Select one of the factors of x2y3 - 11x2y + 6y2 - 66. (x2y + 6) (x2y - 6) (y2 + 11) (y - 3) HELP!!!!
consider \(\Large x^2 y^3 +6y^2\) what can you factor out from these 2 terms ?
okay hold on
\[x ^{2}y ^{3} + 6y ^{2} \]
hold on im still going
holding on :)
\[y ^{2} \left( x ^{2} +6y \right)\]
now am i suppose to factor 6y?
you correctly figured out that y^2 is common and can be factored but you didn't factor out y^2 correctly
i dont understand
\(\Large x^2 y^3 = y^2 \times (x^2 y)\) ^^ got that ?
\(\Large 6y^2 = y^2 \times (6)\)
but what about the 6?
oh neva mind
tell me if you have any doubts, make sure you understand whats going on ...
\(\Large x^2y^3 +6y^2 = y^2 (x^2 y)+ y^2 (6) \\ \Large \color{red} = y^2 (x^2y+6)\)
makes sense ?
oh yeas thank you i know what i did wrong i put the y with the six when i wasnt suppose to because it was already factored out correct?
correct :) and you also missed one 'y' with x^2, because only 2 y's out of y^3 was factored, one still remains
oh okay so the correct answer would be a?
thats right :) A is correct option.
thank you so much i have other questions but i want to make sure that you get medals and stuff so ill keep posting will you be online?
i'll help until i am online :) and welcome ^_^
okay :)
Join our real-time social learning platform and learn together with your friends!