Given the trinomial 5x2 - 2x - 3, predict the type of solutions.
Two rational solutions
One rational solution
Two irrational solutions
Two complex solutions
I don't understand!
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hartnn (hartnn):
for a trinomial
\(\Large ax^2 +bx+c\)
find out
\(\huge D = b^2 -4ac\)
OpenStudy (anonymous):
okay what would d stand for though?
hartnn (hartnn):
if D is Negative, then 2 complex solutions
if D is Positive, then Real Solutions
if D is a perfect square , then Rational Solutions
IF D is =0 , then only one solution
hartnn (hartnn):
compare \(\Large 5x^2 -2x-3\)
with
\(\Large ax^2+bx+c\)
fins a,b,c
can you ?
OpenStudy (anonymous):
okay
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hartnn (hartnn):
**find a,b,c
hartnn (hartnn):
need help with that ?
OpenStudy (anonymous):
no sorry for taking so long i was talking to someone
OpenStudy (anonymous):
a=5
b=-2
c=-3
Is this correct?
hartnn (hartnn):
absolutely correct :)
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OpenStudy (anonymous):
cool okay let me try this
hartnn (hartnn):
now find \(D = b^2-4ac = ..\)
OpenStudy (anonymous):
\[D=-2^{2}-4\left( 5 \right)\left( -3 \right)\]
OpenStudy (anonymous):
\[D=-2^{2}-4\left( -15 \right)\]
hartnn (hartnn):
careful with the brackets !
\(D = (-2)^2 - 4 (5)(-3)\)
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OpenStudy (anonymous):
\[D=-2^{2}+50\]
OpenStudy (anonymous):
oops sorry
OpenStudy (anonymous):
\[D=\left( -2 \right)^{2}+50\]
OpenStudy (anonymous):
\[D=-4+50\]
hartnn (hartnn):
noooo
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OpenStudy (anonymous):
oh crap
hartnn (hartnn):
its
\(\Large b^2\)
and b = -2
so it'll be
\((-2)^2 \)
hartnn (hartnn):
\((-2)^2 = (-2)\times (-2) =+4\)
makes sense ?
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
so i just had to make it positive
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OpenStudy (anonymous):
\[D=4+50=54\]
hartnn (hartnn):
\(\Large -4 (5)(-3) = -4 (-15) = +60\)
OpenStudy (anonymous):
wow i was really off
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
okay so it would be 64
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hartnn (hartnn):
not much :) mistakes happen, that only means you're learning :)
hartnn (hartnn):
yes D =64
OpenStudy (anonymous):
so it would be b?
hartnn (hartnn):
now what is D (64) among these?
if D is Negative, then 2 complex solutions
if D is Positive, then Real Solutions
if D is a perfect square , then Rational Solutions
IF D is =0 , then only one solution
OpenStudy (anonymous):
b
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hartnn (hartnn):
b : One rational Solution ??? NO
we have one solution when D =0
OpenStudy (anonymous):
but what does it mean if it is a perfect square?
hartnn (hartnn):
is 64 a perfect square ?
or you wanna know what is "perfect square"
OpenStudy (anonymous):
what would be considered a perfect square?
hartnn (hartnn):
a perfect square is a number whose square root is an integer
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hartnn (hartnn):
like 25 is a perfect square
because
\(\sqrt {25} = 5\)
hartnn (hartnn):
whether 2 is not a perfect square because \(\sqrt {2} = 1.414\)
and 1.414 is not an integer
hartnn (hartnn):
whats \(\sqrt {64} =.. ?\)
you know ?
OpenStudy (anonymous):
8
hartnn (hartnn):
is 8 an integer ?
if yes, then 64 is a perfect square :)
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OpenStudy (anonymous):
8 is an integer
so you wouldnt have to completely break it down in order to know?
hartnn (hartnn):
i didn't get your question .. .
hartnn (hartnn):
if D is a perfect square , then 2 Rational Solutions
OpenStudy (anonymous):
oh i got it okay thank you so much for your help!!!