Question

The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative.

Answer 1

please, you have to calculate the first derivative of s(t), so
what is:
\[\frac{ ds }{ dt }=...\]

Answer 2

is the answer -6?

Answer 3

@SolomonZelman

Answer 4

yes!

Answer 5

ok. just changed the -6t to x and did d/dx(-6x) and got -6 and the -2 is 0

Answer 6

can i ask another question? @Michele_Laino
Use graphs and tables to find the limit and identify any vertical asymptotes of limit of 1 divided by the quantity x minus 7 squared as x approaches 7.

Answer 7

ok!

Answer 8

or 1/(x-7)^2

Answer 9

finding the limit and and vertical asymptotes. i got 1 as the limit and 7 as any vertical asymptote

Answer 10

is that correct?

Answer 11

vertical asymptote x=7 is right!
limit when x is going to?

Answer 12

x->7

Answer 13

\[x\]

Answer 14

\[x \rightarrow 7\]

Answer 15

we can only calculate this limit:
\[\lim _{x \rightarrow 7+}\frac{ 1 }{ \sqrt{x-7} }=+ \infty\]
since domain of your function is the set of all real x such that: x>7

Answer 16

namely limit when x goes to 7 from right!

Answer 17

ok. thanks for the help. i'll give you a medal and fan you if you want.

Answer 18

thanks!

Answer 19

that sounds wrong. *i will become a fan

Answer 20

ok!

Answer 21

whats wrong in fanning someone ? O.o :P