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Mathematics 9 Online
OpenStudy (anonymous):

Derivative question help.

OpenStudy (anonymous):

OpenStudy (anonymous):

@cwrw238

OpenStudy (anonymous):

I don't actually understand what [d] and [b] are supposed to be?

OpenStudy (surry99):

can you take the first derivative?

OpenStudy (anonymous):

Umm 4([d]x+[b])^3 * ([d]) ?

OpenStudy (anonymous):

And then we derivate it again?

OpenStudy (surry99):

yes

OpenStudy (anonymous):

Is there any way to solve this on some calculator?

OpenStudy (cwrw238):

yes thats the first derivative assuming [d] and [b] are constants

OpenStudy (cwrw238):

not that i know of

OpenStudy (anonymous):

wolfram something?

OpenStudy (surry99):

you really need to learn to do it by hand to learn the rules of differentiation

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

Please help me with this too

OpenStudy (anonymous):

OpenStudy (cwrw238):

you perform the second derivative in a similar way to the first - use the chain rule

OpenStudy (surry99):

you need to take the second derivative for the first question. you only took the first derivative.

OpenStudy (anonymous):

@surry99 thanks I'll solve that. Please help me with the second one

OpenStudy (anonymous):

@cwrw238 which question are you referring to?

OpenStudy (cwrw238):

the first one

OpenStudy (anonymous):

thanks i got that. pleasae see the other one now

OpenStudy (anonymous):

WAIT ARE D AND B GREATEST INTEGER FUNCTIONS???

OpenStudy (anonymous):

idk this is what it says

OpenStudy (anonymous):

lets for the sake of sake change the question

OpenStudy (anonymous):

\[7x-4/3x+6\]

OpenStudy (anonymous):

where a=7 b=4 c=3 d=6

OpenStudy (anonymous):

from where did you get these values?

OpenStudy (anonymous):

they can be any values........it doesnt matter

OpenStudy (anonymous):

wait. no we cant change them

OpenStudy (anonymous):

okay fine we go ur way

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

where are u stuck xactly??

OpenStudy (anonymous):

Wait. now i get you. thanks, @cambrige

OpenStudy (anonymous):

Can you help me with more

OpenStudy (anonymous):

hit me

OpenStudy (anonymous):

hahah. even if its hard?

OpenStudy (anonymous):

no problem........m dat good

OpenStudy (anonymous):

lmao

OpenStudy (anonymous):

lmao

OpenStudy (anonymous):

we use chain rule in q1 or something like that?

OpenStudy (anonymous):

i think something like dx/dy = dx/dt * dt/dy ?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

u neednt explain just hit me

OpenStudy (anonymous):

but where it says that? because it asks for magnitude and direction

OpenStudy (anonymous):

?

OpenStudy (anonymous):

sry

OpenStudy (anonymous):

lag m back

OpenStudy (anonymous):

ya so u diffrntiate it with respect to t

OpenStudy (anonymous):

whats the problem??

OpenStudy (anonymous):

wait ur therE??

OpenStudy (anonymous):

so yeah first diffrntiate the individual functions wrt t

OpenStudy (anonymous):

wait...........are x and y the distances covered??

OpenStudy (anonymous):

if yes then u neednt differentiate

OpenStudy (anonymous):

its asking velocity.okay then

OpenStudy (anonymous):

find dx/dt find dy/dt at t=3

OpenStudy (anonymous):

then use pythagoras theorem to find the net velocity!!

OpenStudy (anonymous):

11 comments from me..where u at??

OpenStudy (anonymous):

Sorry, I'm back.

OpenStudy (anonymous):

how to find the direction again?

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

what did u get after u differentiate??

OpenStudy (anonymous):

Dirn depends upon the sign of the final answer

OpenStudy (anonymous):

I didn't do it yet. :P

OpenStudy (anonymous):

Lets say we get -2 as our answer. then what do we do?

OpenStudy (anonymous):

u do it u get it.....easy peesy Japaneesy.........n

OpenStudy (anonymous):

Noooo. the direction

OpenStudy (anonymous):

lol.........differentiate it and temme the ans

OpenStudy (anonymous):

Nooooo.

OpenStudy (anonymous):

U gotta do it...only then will I xplain

OpenStudy (anonymous):

dx/dt and dy/dt

OpenStudy (anonymous):

okay..:c

OpenStudy (anonymous):

Can you give me ten minutes? i will brb. will you be here

OpenStudy (anonymous):

mostly no.......but

OpenStudy (anonymous):

lets see

OpenStudy (anonymous):

Listen

OpenStudy (anonymous):

@cambrige

OpenStudy (anonymous):

OMG! Thank God you're here.

OpenStudy (anonymous):

yes??

OpenStudy (anonymous):

thats not 10 mins u know!!

OpenStudy (anonymous):

I'm sorry. Forgive me.

OpenStudy (anonymous):

So this one says to give answer to two decimal places? http://assets.openstudy.com/updates/attachments/54a2db94e4b054f0c3b45c14-jessyjessy-1419959931449-capture.png

OpenStudy (anonymous):

yes simple round off

OpenStudy (anonymous):

whats the problem in that??

OpenStudy (anonymous):

HOW?

OpenStudy (anonymous):

Should we suppose values for [a], [b], etc?

OpenStudy (anonymous):

no no

OpenStudy (anonymous):

UNLESS ASKED

OpenStudy (anonymous):

Then how to answer to two decimal places?

OpenStudy (anonymous):

first differentiate it girl

OpenStudy (anonymous):

temme what u get

OpenStudy (anonymous):

I did.

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

again.......temme what u got

OpenStudy (anonymous):

argh....okay

OpenStudy (anonymous):

lol

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