The population f(x), in millions, of State A of a country after x years is represented by the function shown below:
\[f(x)=2(1.08)^{t}\] The graph shows the population g(x), in millions, of State B of the country after x years:
Which conclusion is correct about the population of State A and State B? (A) The original population of State B was half of the original population of State A. (B) The original population of State A was half of the original population of State B. (C) The original population of State A was equal to the original population of State B. (D) The original population of State B was one-fourth of the original population of State A.
@cwrw238 @hartnn @Zarkon @iambatman @ganeshie8 I need help with this. Please explain this problem to me.
I think you have to graph the function of State A and then compare the graphs.
Doing in my head, the function of f(x) = g(x)'s graph making letter C the correct answer.
I don't think C could be the answer.
\[f(x) = 2(1.08)^{t}\] Say 0 years has passed, t = 0 \[f(x) = 2(1.08)^{0}= 2(1)=2\]
f(x) graph, (x, y) = 0, 2 g(x) graph (x, y) = 0, 2 Just to be sure, Imma get somebody @Directrix
\[f(x)=2(1.08)^{t}\]
is equal to \[f(x)= 2(1)^{0.08t}\]
@iGreen @paki I really need help on this.
@pooja195 can u help me plz?
@hartnn
yes original population of both states = 2 they are equal :)
Can you explain? I dont really understand it tho. @Sadworld said that it was C also.
original population means population at t=0 for sate A , when t = 0 \(2 (1.08)^0 = 2\) because anything^0 =1 (except 0)
for state B, its the y intercept, the point at which graph cuts y axis which is clearly 2 :)
Ohhhh, ok. Thank you so much @Sadworld @hartnn @pooja195!! :)
thanks @pooja195 :)
lol i didnt do anything but your welcome
@hartnn yr welcome :)
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