Question

HELP
@Godlovesme
write an equation in slope-intercept form of a line that passes through the given point and is perpendicular to the graph of the given equation.
(-4,3); y=1/4x-4
Write an equation for the perpendicular line in slope intercept form.

Answer 1

r u familiar with the point-slope form

Answer 2

just kidding it is:
y2-y1=m(x2-x1)

Answer 3

@Godlovesme

Answer 4

@monsterfox1997
@CausticSyndicalist
@poopsiedoodle
@NeonStrawsForever

Answer 5

sorry my internet was slow =0 u r right @kyley_bear
do u know what y1, x1, and m stands for?

Answer 6

I know that m is slope. but dont know what x1 and y1 are.

Answer 7

Its okay my internet always gets super slow when i get on openstudy.

Answer 8

x1 is ur given x-coordinate when y is ur y
in this case we r given (-4,3)

Answer 9

perpendicular lines have negative reciprocal slopes frist

Answer 10

as @AlexandervonHumboldt2 said perpendicular lines have actually opposite and reciprocal slope
we r given 1/4 so the perpendicular will be -4 confused @kyley_bear

Answer 11

.... a little i get what y1 and x1 are but what does the negative reciprocal thing have to do with this. it is just consfusing me..

Answer 12

those are perpendicular lines cuz one is increasing(+ve slope) if u look closely while the other is decreasing(-ve slope) can u c that

Answer 13

ohhh okay so the lines making the perpendicular line are pointing in a negative and a positive direction.

Answer 14

yes @kyley_bear since we have slope of -4 and an ordered pair pf (-4,3) can u set up an equation

Answer 15

@kyley_bear u there?

Answer 16

yeah my comp is messing up sorry

Answer 17

its okay i understand

Answer 18

im back @kyley_bear

Answer 19

@Godlovesme I had to leave to lol I am back. this is like phone tag xD

Answer 20

lol :)

Answer 21

okay so what do i need to do?

Answer 22

use the point-slope formula
we have slope = -4
y1--> 3 and x1 --> -4
y-y1= m(x-x1)
y-3=-4(x- - 4)
can u solve from there? :)