Please help me solve this. f-1(3) when f(x) = 2x plus 3, all over 5
To find the inverse: Replace f(x) with y Switch x's and y's, so put x where y is and x where y is. Solve for y Replace y with f^-1(x)
Once you find the inverse plug in 3 for the function.
what?>>
\[f(x)=(2x+3)^5?\]
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Ok, so follow my steps I have put and see what you get for the inverse first.
so you put a y where the x is?
Yeah you interchange them
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take f(x)=3
find x
substitube for y
then subtitute in the main equation
so 2(3)+3 / 5?
no no
@iambatman U take this
Sorry im really trying to get this its my second to last question in this class ever
Let f(x)=y
\[f(x) = \frac{ 2x+3 }{ 5 } \implies y = \frac{ 2x+3 }{ 5 }\] No worries, I think he just confused you more, so just follow the steps I gave you, now interchange.
Did that part deal with the f^-1?
What part? We haven't gotten there yet, all we did was let f(x) = y
okay. So what do i do after that?
Now we switch x's and y's
So put x's where the y is and put y where the x is.
oh this is like a 2 part problem, you solve it twice kinda thing?
for one you solve for x and the other you solve for y?
I guess you can think of it that way :)
Well, not quite
You're just switching the variables and solving for y, and then letting it equal f^-1(x)
im lost sorry
Try doing the problem, with the steps I gave you earlier, and if you want more detail in what exactly a inverse function is, just read this: http://www.mathsisfun.com/sets/function-inverse.html
okay i kinda get it now
DUDE I didnt mean to confuse u more man.....lol
you didn't. I didn't understand it in the first place. Im doing algebra 2 when ive just started algebra 1
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