Can someone check my answer for this?
I got aprx 121
No I think It's wrong answer First find the area of the rectangle
then subtract the area of the 2 semi circle which actually is one circle its radius half of the width
Not 121 or close unfortunately. Do what @ghaida suggested.
\[\sf \text{Area of rectangle} = A= l\cdot w\]\[\sf \text{area of circle} = A= \pi r^2~,~ r = \frac{D}{2}\]
@heythatsness Do you have a revised answer for this problem or do you want to start over at the beginning?
I have 420 for the area of a rectangle
And now find the area of the 2 semi circles, or rather, full circle.
I got 153.94 for one semi circle
and since there's two I add them both and get 307.88?
Good, now subtract the area of the rectangle - area of the 2 semicircles (full circle)
That gives you the area of the paper that remains.
I got 266.06
Let's check:
\[420 - 49\pi = 266.06 ~\checkmark\]
Good job :)
Thanks for helping!
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