Rewrite with only sin x and cos x. cos 3x
@hartnn
hmm let me think
help me @AlexandervonHumboldt2
maybe write it as cos(2x + x) :- cos(2x + x) = cos2x cos - sin2x sinx - not sure - now we have sines involved
oh - thats ok lol
now we can use cos2x = 2cos^2x - 1 and sin2x = 2 sinx cosx
Hmmmmm...... Would that be all?
well substitute for cos 2x and sin 2x and you'll have your answer
cos3x = cos(2x + x) = (2 cos^2x - 1) cos - 2 sinx cos x cos x = 2 cos^3 x - cos x - 2 sinx cos^2 x
Here are two equations you should memorize, they let you reduce angles down. So start out with cos(x+2x) and then use the formulas again to get rid of the sin(2x) and cos(2x) that pop up. \[\Large \sin(x+y)=\sin x \cos y + \sin y \cos x\\ \Large \cos(x+y)=\cos x \cos y - \sin x \sin y\]
If you have time, there's actually a very simple way of deriving these equations.
Ok, so using that formula I come up with \(cos(x+2x)=cosx~cos2x-sinx~sin2x\)
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