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Mathematics 13 Online
OpenStudy (anonymous):

Was wondering, I think this statement (in the comments) is true. I think it is, and I am pretty sure. Confrim please....

OpenStudy (anonymous):

\[\LARGE c_{_1} \times \sum_{n=c_{_2}}^{c_{_3}}f(n)= \sum_{n=c_{_2}}^{c_{_3}} c_{_1} \times f(n)\] (where \[\large c_{_1}~,~ c_{_2}~,~ c_{_3},\] are just 3 numbers that can be, but not necessarily equal to each other) and assuming that \[ \large c_{_1}\ne 0,~~1\]

OpenStudy (anonymous):

\[\large {\rm and} {~~c_{_3}} {\rm~~is~~a~~nat ural~~number. }\]

OpenStudy (anonymous):

whoa

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

the notations?

OpenStudy (anonymous):

YA

OpenStudy (anonymous):

plus ur rt

OpenStudy (anonymous):

basic summation FORMULA

OpenStudy (anonymous):

I like to be precise....

OpenStudy (anonymous):

yes, that is true, then.

OpenStudy (anonymous):

hmm.tru dat

OpenStudy (anonymous):

but you are saying, it's something I should have known

OpenStudy (anonymous):

there's also a product formula...I think I forgot

OpenStudy (anonymous):

we all shud know these.....

OpenStudy (anonymous):

surely:) I was just trying to appeal to my own logic

OpenStudy (anonymous):

hmm lol man

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