Question

my next problem is +++

Answer 1

\[\int\limits_{ }^{ }x \sec^2x~dx\]~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Answer 2

integration by parts :)

Answer 3

yup, tnx:)
\[\int\limits_{ }^{ }x \sec^2x~dx=x \sec^2x - \int\limits_{ }^{ }\tan x~dx\]\[\int\limits_{ }^{ }x \sec^2x~dx=x \sec^2x - \int\limits_{ }^{ }\tan x~dx=x \sec^2x-\ln(\cos x)+C\]

Answer 4

wow, I integrated tanx in my head lol!!

Answer 5

I made a mistake it is positive ln(cos x)

Answer 6

because
u=cos(x)
-du=sin(x) dx <<<<<

Answer 7

\[\int\limits_{ }^{ }x \sec^2x~dx=x \sec^2x+\ln(\cos x)+C\]

Answer 8

yes:)

Answer 9

tnx for looking y'all, got another one