Question

last one for tday

Answer 1

\[\int\limits_{ }^{ } \frac{1}{x~\ln x(\ln x~-1)}~dx\]

Answer 2

hint please?

Answer 3

Derivative of log is...

Answer 4

ln(x) ' = 1/x

Answer 5

substitute u = ln x

Answer 6

du = 1/x dx

Answer 7

ok, then it becomes very good to solve, tnx

Answer 8

I see I see

Answer 9

:)

Answer 10

pellett clicked something

Answer 11

\[\int\limits_{ }^{ } \frac{1}{u(u~-1)}~du\]

Answer 12

then,
\[A(u)+B(u-1)=1\]

Answer 13

A=1
B=-1

Answer 14

\[\int\limits_{ }^{ } \frac{1}{u-1}-\frac{1}{u}~du\]

Answer 15

then,
\[\color{red}{\ln( \ln x -1)-\ln(\ln x)+C}\]

Answer 16

right?

Answer 17

noooooooo I missed it

Answer 18

you missed the prob, but did i miss anything?

Answer 19

9+10 ok

Answer 20

shut up, jk

Answer 21

alright, I am out, will get suspended anyways, wouldn't?