@DanJS
this is B right? i just did this question with someone else but they were wrong for the last couple.. hahah
Try to graph f ' (x) from that description
|dw:1419990603852:dw|
doesnt have to be linear, but it is decreasing
First choice: f(x) has an inflection point at x=0?
that means that the concavity will change at x=0
Think of f'(x) as the velocity of an object.... The velocity starts out positive, then keeps decreasing, going to zero velocity , then keeps getting more negative velocity
The object is going in one direction and slows down to a stop and goes the other direction
so the position function of that description looks kina like say a parabola
Throwing a ball, starts at a huge + velocity, and has a constant acceleration opposing the motion, the ball slows to a stop (top of parabola) (where f '(x) = 0) and accelerates at the same constant rate in the opposite direction
|dw:1419990917482:dw|
see how if the f '(x) is constantly decreasing, with an initial positive value, that it describes the curved graph above
f ' (x) is the rate of change at any point on f (x)
the rate of change at f '(x) is the same as the horizontal tangent at the top of the curve of f(z)
Now that you can visualize what f looks like, take each answer one at a time
Inflection at x=0? concavity changes, NO, it is always concave downwards
lol are you kinda with me ?
The graph has a relative maximul at x=0? looks like it
oops didnt read that right hahhha
the graph is always concave down...YES
There are no inflection points on the graph of f... so the first one is the False one
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