Can you explaing me how: tan^-1(2/2)=pi/4 How became tan^-1(2/2) in pi/4. originary exercise complex number z^9=2+2j
can u tell what is the orignal question
Ok one momente a make a photo.
\[\tan^{-1}(\dfrac{2}{2})\\=\tan^{-1}(1)=45^{\circ}=\dfrac{\pi}{4}\]
ok and how 45 grade in pi/4?
its on the unit circle
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suppose this is right angled triangle and here it is also iscoceles triangle so the two sides opposite to \(45^{\circ}\) are equal now we know that \(\tan \theta =\dfrac{opposite~ side}{adjacent~side}\) so \(\tan 45^{\circ} =\dfrac{a}{a}\) \(\tan 45^{\circ} =1\\\) hence \(45^{\circ}=\tan ^{-1} 1\)
and \(45^{\circ}\) in radian is \((\dfrac{\pi}{4})\)
can I make it without calculator?
or onliy wiht calclator?
which thing ?
a sorry radians
well the idea is that \(\pi\) radian is equal to \(180^{\circ}\) to \(~~~~~\dfrac{\pi}{4}\\ =\dfrac{180}{4}\\ =\dfrac{90}{2}\\ =45^{\circ}\)
or conversly \(\pi\) radian is equal to \(180^{\circ}\) \(~~~~~45^{\circ}\\ =45\times \dfrac{\pi}{180}\\ =\dfrac{\pi}{4}\\ \)
ok only one thing about it
than I divide 45pi/180 by 45 ?
a ok I understand. also Pi must be alone without number?
\(\pi\) is not alone it has some value like \(3.14..\) but we usually write angles in it in the degrees \(\Huge \theta ^{\circ}\) symbol \(\huge \pi\)
yes ok that is so
but I mean the number before pi
by every exercise liek this I must divide from Pi. the pi must stay alone wihtout other numbers?
for example if u have to to write \(360^{\circ}\) in radian then it can be written as \(\Large 360^{\circ}\\ \Large =360\times \dfrac{\pi}{180}\\ \Large =2\pi\\\)
a ok I understand thank you very much what arguments I must study for this exerscise? I understand all but I will study it for sin and cos
here is a good link for u http://www.mathsisfun.com/geometry/unit-circle.html
at first trignometry is difficult,but once u practice , it will be as easy as \(1+1=2\)
Ok will do but first I must study relevant things for test. thanky you
welcome
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