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help me please..the question is at below...
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@studyboy5255 Have you done calculus yet?
what do you mean?
|dw:1420038858319:dw|
he is taking calc
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you'd be using calculus to solve the problem, is that appropriate?
I have answered his L'H'S limit question
go for it, math:)
@studyboy5255 Referring to the diagram, L=a+b so \(\large L=\frac{4}{\cos(\theta)}+\frac{3}{\sin(\theta)}\) ok so far?
what is the angle?
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@studyboy5255 Since you're busy, I will give you the rest of the procedure. You can post for answer check. Equate \(\frac{dL}{d\theta}=0\) and solve for theta. You can solve for \(\theta\) easily by factorizing, using \(A^3-B^3=(A-B)(A^2+AB+B^2)\)
The angle is between 40 and 50 degrees.
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