HELP ASAP WILL GIVE MEDAL AND BE FAN If Greg rolls four dice, what is the probability that he rolls more 1's than 6's?
okay
u know what will be the individual probability??
What is that?
like if u roll one dice
what is the probablity if u roll one dice for the given constraints?
If you roll one dice, then you can't have more. There's only one number to base it on.
first find prob of rolling 1
then prob of rolling 6
1/6
I am little rusty in probability...hold on
1 dice - probability of any number is 1/6 4 dices - probability of any number is 4/6 so the probability is the same for any number
Does this mean that the probability is 4/6?
@Fallontine it says how many more 1s than 6s??
how do u interpret that??
ammm... wait...
ok..:)
this is a permutation
oh......so how did u proceed??
prob of finding 1=1/6 of finding 6=5/6
for one dice
noooo... it's 1/6 for 1, 1/6 for 2 etc... and 1/6 for 6 coz you have 6 numbers and you have to choose 1 and the probability is the same for all of them
I know, what permutation is this??
Wait, can't we do casework?
We can consider the various cases where there are more ones than sixes - one dice with a 1 and no dice with 6s - two dice with 1s and no dice with 6s - two dice with 1s and one dice with 6 - three dice with 1s and no dice with 6s - three dice with 1s and one dice with 6 - four dice with 1s
no no after u have chosen 1/6 for 1 6 can be anywhere in the rest 5 numbers hence 5/6
Is that right??
@Fallontine
Hello? :)
it seems you just need to find how many ways the outcome can have more 1s than 6s and divide that by the total number of possible outcomes
Oh yeah! Just a sec while I figure it out.
1111 1116 1161.....like that
@TuringTest Thank u .I got it
How many possible outcomes are there? @TuringTest
1116, 1161, 1611, 6111, 1111 five outcomes with more 1s than 6s
I mean the number in the denominator.
well how many total ways can one throw the dice? there are 6 possible outcomes for the first die 6 outcomes for the second die, etc
Oh, so 6^4
when you flip a coin, the number of different outcomes you can get is 2^n where n is the number of flips yep :)
you also have to count with the other numbers (2 to 5) there are many many possibilities with no 1 or 6 at all
indeed, I forgot to count 11x6, 1xxx, and so on my mistake
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