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Chemistry 8 Online
OpenStudy (anonymous):

How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2? (4 points) Unbalanced equation: Mg + O2 → MgO

OpenStudy (anonymous):

@katkipe

OpenStudy (anonymous):

^ lol

OpenStudy (anonymous):

Our equation is 2Mg + O2=2MgO also 4Mg + 2O2=4MgO Atomic mass of Mg is 24.3 & Molecular mass of O2 is 32 which means as per the balanced equation we require 48.6 gram of mg for every 32 gram of oxygen which gives us 2*(24.3+16) gram of MgO & for 97.2 gram of Mg we require 64 gram of oxygen which will give us 4*(24.3+16) ie. 161.2 gram of MgO. Clearly oxygen in excess & Mg is a limiting reagent. Thus we have 161..2 gram of MgO formed.

OpenStudy (anonymous):

/X_x\

OpenStudy (anonymous):

How are there two Mg??

OpenStudy (anonymous):

How do you find Molecular Mass? @katkipe

OpenStudy (anonymous):

Hang on. I am googleing some help.

OpenStudy (anonymous):

Yep I dont know lol. I googled stuff. @Secret-Ninja Can you further help him?

OpenStudy (anonymous):

@pooja195

OpenStudy (anonymous):

Thanks @pooja195 !

pooja195 (pooja195):

no problem :)

OpenStudy (anonymous):

hey you changed your profile pic cx

OpenStudy (anonymous):

She was referring to me... @pooja195 That didn't completely answer my question. I know how to balance the equations, I don't know how to do what it wants afterwards.

pooja195 (pooja195):

Hold on let me look

OpenStudy (anonymous):

kk :)

pooja195 (pooja195):

What dont you get?

OpenStudy (anonymous):

It wants to know how many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2. I think the answer is 97.2 Mg

pooja195 (pooja195):

Can you explain your answer?

OpenStudy (anonymous):

Possibly. When 2 moles of magnesium reacts with 1 mole of oxygen gas, 2 moles of magnesium oxide will be formed. So let's say you mix 10 moles of Mg with 5 moles, you'll get 10 moles of MgO2.

pooja195 (pooja195):

Your correct :)

OpenStudy (anonymous):

LoL thanks, it's hard to find people who don't just give you the answer. Anyone can google it, but others actually like to LEARN the information.

pooja195 (pooja195):

lol I hate giving direct answers and i dont want to get in trouble :) and your welcome

OpenStudy (anonymous):

That problem was with Synthesizing. My next one is on Decomposition. Can you help me with that too?

pooja195 (pooja195):

yes post it again

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