How many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2? (4 points) Unbalanced equation: Mg + O2 → MgO
@katkipe
^ lol
Our equation is 2Mg + O2=2MgO also 4Mg + 2O2=4MgO Atomic mass of Mg is 24.3 & Molecular mass of O2 is 32 which means as per the balanced equation we require 48.6 gram of mg for every 32 gram of oxygen which gives us 2*(24.3+16) gram of MgO & for 97.2 gram of Mg we require 64 gram of oxygen which will give us 4*(24.3+16) ie. 161.2 gram of MgO. Clearly oxygen in excess & Mg is a limiting reagent. Thus we have 161..2 gram of MgO formed.
/X_x\
How are there two Mg??
How do you find Molecular Mass? @katkipe
Hang on. I am googleing some help.
Yep I dont know lol. I googled stuff. @Secret-Ninja Can you further help him?
@pooja195
Thanks @pooja195 !
no problem :)
hey you changed your profile pic cx
She was referring to me... @pooja195 That didn't completely answer my question. I know how to balance the equations, I don't know how to do what it wants afterwards.
Hold on let me look
kk :)
What dont you get?
It wants to know how many grams of magnesium oxide can be produced when 97.2 g Mg react with 88.5 g O2. I think the answer is 97.2 Mg
Can you explain your answer?
Possibly. When 2 moles of magnesium reacts with 1 mole of oxygen gas, 2 moles of magnesium oxide will be formed. So let's say you mix 10 moles of Mg with 5 moles, you'll get 10 moles of MgO2.
Your correct :)
LoL thanks, it's hard to find people who don't just give you the answer. Anyone can google it, but others actually like to LEARN the information.
lol I hate giving direct answers and i dont want to get in trouble :) and your welcome
That problem was with Synthesizing. My next one is on Decomposition. Can you help me with that too?
yes post it again
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