Question

There are 15 members of the show choir. In how many ways can you arrange 4 members in the front row when order does not matter?

Answer 1

\[15(14)(13)(12)\]

Answer 2

It's factorial. I don't know how to explain it but here: http://en.wikipedia.org/wiki/Factorial

Answer 3

nCr

Answer 4

For the first chair 15 possible people can seat down. Since someone already took the 1st chair then for the 2nd chair, there are only 14 possible occupants. So on and so fort.

Answer 5

\(\LARGE\color{black}{{\rm \color{green}{n}C\color{darkgoldenrod}{r}}=\frac{\LARGE {\rm \color{green}{n}}! }{\LARGE{\rm (\color{darkgoldenrod}{r}!)\times(\color{green}{n}-\color{darkgoldenrod}{r})}! } }\)

Answer 6

you are choosing 4 people out of 15. (4=r, n=15)

Answer 7

@dwatts158 plug in your numbers solve and tell me what you get.

Answer 8

ok