Question

How many moles of ethane (C2H6) would be needed to react with 62.3 grams of oxygen gas? (4 points)

Unbalanced equation: C2H6 + O2 → CO2 + H2O

Answer 1

@radar @lizzyrockefeller

Answer 2

I don't want straight answers, I want to learn how to do it, so I can move on & pass my exams in a couple weeks.

Answer 3

okay il do step by step

Answer 4

<3 Thanks xD

Answer 5

your welcome :) it will take me a few okay

Answer 6

Take your time :) At least your helping ccx

Answer 7

so what u would do is balance an write the equation like this 2C2H6 + 7O2 --> 4CO2 + 6H2O then you do the molucule weight of O2 which is 32.00

Answer 8

then after all that you would do 1 Mal of O2=32g 7*32=224g

Answer 9

im not done im just showing step by step

Answer 10

whoa... WHOA slow down :3 so first you balance the equation. This means having equal amounts on the product & the reactant. I'm fairly new to this, so I need help with that first. Please?? :3

Answer 11

okay im sorry

Answer 12

No worries! Like I said, you're a HUGE help as it is, so anything is appreciated. :3

Answer 13

yes you have to have equal amounts

Answer 14

So, to do this, you... multiply? If so, what number would you use, & to what extent?

Answer 15

you would just do 7*32 to get 224g thats it

Answer 16

That's it? Are you certain on this? Just want to be sure, not questioning your excellency, just want to get a high grade!

Answer 17

yes i am sure

Answer 18

can i go on or do u have more questions i dont mind

Answer 19

No! Please, continue!

Answer 20

okay sure will

Answer 21

okay now this 1mole of O2= 32g
7*32=224 g

224 g of Oxygen reacts with 2 moles of ethane
62.3 g of oxygen =2*62.3/224=0.5 moles of ethane
u got it

Answer 22

Two questions. Where does 62.3 g of O2 come from?

Answer 23

the 62.3 of O2 comes from just One molecule instead of 2

Answer 24

AH! Yes, that makes sense. Carry on, love.

Answer 25

what was ur other question

Answer 26

Nevermind, it was lame :@

Answer 27

hah okay

Answer 28

So, is that it?

Answer 29

gimmie a second

Answer 30

:) As you wish.

Answer 31

Do you have to explain it

Answer 32

Unfortunately :/

Answer 33

alright

Answer 34

which part do u want me to explain 1st

Answer 35

@Brostep0s

Answer 36

Actually, this will do fine. I think I can take it from here. Thanks. Hreat help, fit for gods. :*

Answer 37

okayy if u need more help just tag me il be here

Answer 38

Thanks again cx