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Chemistry 14 Online
OpenStudy (anonymous):

WILL FAN AND MEDAL!! the moles of the elements? C12H22O11 1.202 g sample Total mass = 342.297 g Total moles = 0.004

OpenStudy (anonymous):

Is that written right?

OpenStudy (anonymous):

ya I thikn

OpenStudy (anonymous):

12 carbons 22 hydrogens 11 oxygens

OpenStudy (anonymous):

@KamiBug

OpenStudy (anonymous):

I wish I could @EVERYBODY

OpenStudy (***[isuru]***):

ur question seems a bit unclear.... is it something like this ? the number of moles of Carbon , Hydrogen and Oxygen in a 1.202 g sample of C6H12O6 ... or is it something other ?

OpenStudy (anonymous):

yes!! @***[isuru]***

OpenStudy (aaronq):

To find the moles of each element you multiply the number of atoms of that element present in the formula by the total moles. For example, if you had 1 mole of \(\sf \huge C_{12}H_{22}O_{11}\) then you had 12 moles of Carbon, 22 moles of H, and 11 moles of O.

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