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OpenStudy (michele_laino):
I got C
OpenStudy (michele_laino):
I give you the identity to solve this question:
\[\sum_{i=1}^{n}i ^{2}=\frac{ n(n+1)(2n+1) }{ 6 }\]
and:
\[\sum_{i=1}^{n}i=\frac{ n(n+1) }{ 2 }\]
both those formulas can be demonstrated usin the induction principle on n
OpenStudy (michele_laino):
please try this substitution:
\[\cos x=t\]
and use this identity:
\[\sec x=\frac{ 1 }{ \cos x }\]
OpenStudy (anonymous):
so it is C
OpenStudy (michele_laino):
no sorry!
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OpenStudy (anonymous):
i meant d!!
OpenStudy (michele_laino):
furthermore, plea\[\tan x=\frac{ \sin x }{ \cos x }\]se use this identity:
OpenStudy (michele_laino):
why D?
OpenStudy (michele_laino):
can you show your work, please?
OpenStudy (anonymous):
oh then it is B
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OpenStudy (anonymous):
im in a rush please
OpenStudy (michele_laino):
I don't know if it is B
OpenStudy (michele_laino):
\[=\int\limits \frac{ \sin x }{ (\cos x)^{2} }dx=-\int\limits \frac{ dt }{ t ^{2} }=\frac{ 1 }{ t }=\frac{ 1 }{ \cos x }+C\]
after the substitution t=cos x
OpenStudy (michele_laino):
@mondona I understand you, nevertheless please note that I can not give you your answer directly, since the code of conduct