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Mathematics 9 Online
OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

I got C

OpenStudy (michele_laino):

I give you the identity to solve this question: \[\sum_{i=1}^{n}i ^{2}=\frac{ n(n+1)(2n+1) }{ 6 }\] and: \[\sum_{i=1}^{n}i=\frac{ n(n+1) }{ 2 }\] both those formulas can be demonstrated usin the induction principle on n

OpenStudy (michele_laino):

please try this substitution: \[\cos x=t\] and use this identity: \[\sec x=\frac{ 1 }{ \cos x }\]

OpenStudy (anonymous):

so it is C

OpenStudy (michele_laino):

no sorry!

OpenStudy (anonymous):

i meant d!!

OpenStudy (michele_laino):

furthermore, plea\[\tan x=\frac{ \sin x }{ \cos x }\]se use this identity:

OpenStudy (michele_laino):

why D?

OpenStudy (michele_laino):

can you show your work, please?

OpenStudy (anonymous):

oh then it is B

OpenStudy (anonymous):

im in a rush please

OpenStudy (michele_laino):

I don't know if it is B

OpenStudy (michele_laino):

\[=\int\limits \frac{ \sin x }{ (\cos x)^{2} }dx=-\int\limits \frac{ dt }{ t ^{2} }=\frac{ 1 }{ t }=\frac{ 1 }{ \cos x }+C\] after the substitution t=cos x

OpenStudy (michele_laino):

@mondona I understand you, nevertheless please note that I can not give you your answer directly, since the code of conduct

OpenStudy (michele_laino):

bye! :) @mondona

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