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Mathematics 21 Online
OpenStudy (anonymous):

Determine which relation is a function. A. {(–4, 3), (–2, 3), (–1, 2), (2, 5), (3, 2)} B. {(–4, 1), (–2, 3), (–2, 1), (–1, 5), (3, 2)} C. {(–4, 1), (–2, 3), (–1, 2), (3, 5), (3, 2)} D. {(–4, 1), (–2, 3), (–1, 1), (–1, 5), (3, 2)}

OpenStudy (freckles):

for which group of ordered pairs do you see that there is more than one ordered pairs with a common x value?

OpenStudy (freckles):

The groups that you name to the question I just asked will be relations who aren't functions.

OpenStudy (anonymous):

they all have move than one x value

OpenStudy (freckles):

Common was the key word there

OpenStudy (anonymous):

a

OpenStudy (freckles):

For example {(3,5),(2,5),(1,2),(3,-7)} has two ordered pairs that have a common x so this set I just gave as an example is not a function. For example {(3,5),(2,5),(1,2),(4,-7)} has no ordered pairs that have a common x so this set I just gave as an example is a function.

OpenStudy (anonymous):

-2 and 2

OpenStudy (freckles):

A has all the x's are different so A is a function.

OpenStudy (freckles):

There were no common x's in A

OpenStudy (anonymous):

I understand not as hard as I thought, Thank You!

OpenStudy (freckles):

B wouldn't work because you had (-2,3) and (-2,1) C wouldn't work because you had (3,2) and (3,5) D wouldn't work because you had (-1,1) and (-1,5)

OpenStudy (anonymous):

yeah

OpenStudy (freckles):

Like each x can only have one y.

OpenStudy (freckles):

Ok cool

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