Determine which relation is a function. A. {(–4, 3), (–2, 3), (–1, 2), (2, 5), (3, 2)} B. {(–4, 1), (–2, 3), (–2, 1), (–1, 5), (3, 2)} C. {(–4, 1), (–2, 3), (–1, 2), (3, 5), (3, 2)} D. {(–4, 1), (–2, 3), (–1, 1), (–1, 5), (3, 2)}
for which group of ordered pairs do you see that there is more than one ordered pairs with a common x value?
The groups that you name to the question I just asked will be relations who aren't functions.
they all have move than one x value
Common was the key word there
a
For example {(3,5),(2,5),(1,2),(3,-7)} has two ordered pairs that have a common x so this set I just gave as an example is not a function. For example {(3,5),(2,5),(1,2),(4,-7)} has no ordered pairs that have a common x so this set I just gave as an example is a function.
-2 and 2
A has all the x's are different so A is a function.
There were no common x's in A
I understand not as hard as I thought, Thank You!
B wouldn't work because you had (-2,3) and (-2,1) C wouldn't work because you had (3,2) and (3,5) D wouldn't work because you had (-1,1) and (-1,5)
yeah
Like each x can only have one y.
Ok cool
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