Question

Simplified form of...?

Answer 1

the things on top are 1's lol
will medal!

Answer 2

please note that:
\[\frac{ 1 }{ b }+\frac{ 1 }{ a }=\frac{ a*1+b *1}{ ab }=\frac{ a+b }{ ab }\]
since the least common multiple is ab

Answer 3

and:
\[\frac{ 1 }{ b }-\frac{ 1 }{ a }=\frac{ a*1-b*1 }{ ab }=\frac{ a-b }{ ab }\]
since the least common multiple is ab again
so your expression is equal to:
\[\frac{ \frac{ a-b }{ ab } }{ \frac{ a+b }{ ab } }=\frac{ a-b }{ ab}*\frac{ ab }{ a+b }=...\]
namely the first fraction times the inverse of the second fraction

Answer 4

so when I apply that to the denominator, would it be a+b/a-b?

Answer 5

no, sorry! please retry!