Write an equation in slope-intercept form of the line with an x-intercept of 6 and a y-intercept of 5.
@Secret-Ninja
I think you already asked this one before....
idk but i need help what isthe formula
For slope: (y-y1) = m (x-x1) = m Standard slope form: y=mx+b
x-intercept of 6 = (6, 0) y-intercept of 5 = (0, 5)
ok thank you
No problem. :)
so m=6?
Actually, its 6/5 which is 1.2 in decimal form
If you subtract 0 it stays the same.
A. y = 6x + 5 B. y = -5/6 x + 5 C. y = -6x + 5 D. y = 5/6 x + 5
so its not a or c
so d?
confused now .-.
is it d or not
Here is the explanation from the beginning. The slope-intercept form of the equation of a line is: \(y = mx + b\), where m is the slope, and b is the y-coordinate of the y-intercept. You are given the intercepts, so using those two points, you can find m, the slope. \(m = \dfrac{y_2 - y_1}{x_2 - x_1} \)
The x-intercept gives you point: (6, 0) The y-intercept gives you point: (0, 5) Now we find the slope: \(x = \dfrac{0 - 5}{6 - 0} = - \dfrac{5}{6}\)
is it d? and ok its b?
Now that we have the slope, and we know the y-intercept is 5, we just use the slope-intercept equation and plug in our values: \(y = mx + b\) \(y = -\dfrac{5}{6}x + 5\)
BTW, two responses above, I meant to write m = the fraction of the slope, not x.
i under stand but is b correct???
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