Question

A 68.4-g sample of potassium chloride was added to 200.0 g of water at 20 degrees Celcius. Is the solution saturated, unsaturated, or supersaturated? Use the table to answer this question.

Please explain!

I know that solubility is the property of a solute to dissolve in a solvent to form a homogeneous solution of the solute in the solvent.

Answer 1

is there any other information available?

the solubility is 344 g/L (20 °C)

http://en.wikipedia.org/wiki/Potassium_chloride

you have \(\sf \dfrac{68.4~g}{0.2~L}=342~g/L\)

Answer 2

Oh I am so sorry! I forgot the table!

Answer 3

so locate KCl in the table, now compare the value given to the value you have.

the units are what you are to watch for "\(\sf g/100~g\)"

for every hundred grams of water you can dissolve 34.2 grams of KCl.

you have 68.4 g of KCl, and 200 grams of water. Get the value in terms of 100 grams of water:

\(\sf \dfrac{68.4~g}{2}=34.2~g/100~g~H_2O\)

Answer 4

So it is saturated?

Answer 5

@aaronq is this correct?

Answer 6

yes

Answer 7

Okay. Thank you so much!

Answer 8

no problem!