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Mathematics 18 Online
OpenStudy (jolo_yolo):

Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h. Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. Part B: How can you graph the equation obtained in Part A for the first seven hours?

OpenStudy (turingtest):

ok, so I am guessing we can use point-slope formula

OpenStudy (jolo_yolo):

yeah. Im stuck now, idk what my next steps are since I've figured out the slope

OpenStudy (turingtest):

point-slope formula is\[y-y_1=m(x-x_1)\]so pick a point \((x_1,y_1)\) and plug it into the formula

OpenStudy (jolo_yolo):

okay so (3,53). Is it like 53 - 53(1) = 3(3 - 3(1)) ?

OpenStudy (turingtest):

no, you only plug in for \((x_1,y_1)\), you leave the regular \(x\) and \(y\) alone; we need them for the graph

OpenStudy (jolo_yolo):

oh k, 53 - y1 = 3(3-x1)

OpenStudy (turingtest):

you plugged into x and y, but you need to plug into \(x_1\) and \(y_1\)

OpenStudy (jolo_yolo):

sorry i got that confused at first; y - 53 = 3(x - 3)

OpenStudy (turingtest):

good, now solve it for y

OpenStudy (jolo_yolo):

y=3(x-3) + 53; correct?

OpenStudy (turingtest):

yeah, but simplify the right side

OpenStudy (jolo_yolo):

y=3x + 44

OpenStudy (turingtest):

good, now what does x represent?

OpenStudy (jolo_yolo):

not sure, one of the points I think

OpenStudy (turingtest):

x is the left coordinate in our pairs in the pair (3,53) what does the 3 represent?

OpenStudy (jolo_yolo):

hours?

OpenStudy (turingtest):

yes, and y represents...?

OpenStudy (jolo_yolo):

km or kilometers

OpenStudy (turingtest):

km/hr actually

OpenStudy (turingtest):

sorry i meant let's say x=time and y=velocity

OpenStudy (turingtest):

|dw:1420068833152:dw|

OpenStudy (turingtest):

what is the speed of the car at time zero (i.e. at x=0) ?

OpenStudy (jolo_yolo):

uh idk, 0?

OpenStudy (turingtest):

no, use the formula we just developed y=3x + 44

OpenStudy (jolo_yolo):

44?

OpenStudy (jolo_yolo):

@TuringTest

OpenStudy (turingtest):

ah yes, very good let's mark that on the graph|dw:1420069303522:dw|what about at time equals one hour?

OpenStudy (jolo_yolo):

you mean as 1 for x?

OpenStudy (turingtest):

yep

OpenStudy (jolo_yolo):

47

OpenStudy (turingtest):

great, so let's mark that|dw:1420069483760:dw|are you seeing where this is going?

OpenStudy (jolo_yolo):

it's increasing by the hour? .-.

OpenStudy (turingtest):

sure, in the problem we see that it was going faster after 6 hours than after 3 hours, so it is accelerating

OpenStudy (jolo_yolo):

accelerating, right

OpenStudy (turingtest):

so just plug in the rest of the times and write down the corresponding speeds

OpenStudy (jolo_yolo):

oh okay so for part A my answer is y=3x + 44 and for par B i plug in 7 for x, right?

OpenStudy (turingtest):

well they want you to explain "how to graph it" so you need two points that you can draw a line though so get the endpoints of x=0 and x=7 and draw a line through them

OpenStudy (jolo_yolo):

Alright, got it, Thanks ! much appreciated

OpenStudy (turingtest):

welcome!

OpenStudy (chrisga):

what was part B?

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