Question

i give metals

Answer 1

Which system of equations is represented by the graph?

Answer 2

@freckles

Answer 3

@triciaal i need help with this one

Answer 4

Okay, so you have a line with 2 points: \(\normalsize\color{blue}{ \rm (-6,7) }\) and \(\normalsize\color{blue}{ \rm (-1,2) }\) . You should be able to find the line by first finding the slope and then the y-intercept.

The parabola, can be found as well:
It will be some \(\normalsize\color{blue}{ \rm y=x^2 ... }\) since it is second degreee and opens up

Answer 5

You need to figure out the scale factor by which you stretch.
\(\normalsize\color{blue}{ \rm (-3,-2) }\) is the vertex.
\(\normalsize\color{blue}{ \rm (-1,2) }\) is another point,
and y intercept \(\normalsize\color{blue}{ \rm (0,6) }\)

I can make a reasonable guess for a stretch factor to be 1.
\(\normalsize\color{blue}{ y=(x+3)^2-2 }\)

Answer 6

oh that doesn't work

Answer 7

would the answer be y = x2 + 6x – 7x – y = 1

Answer 8

\(\normalsize\color{blue}{ 6=a(0+3)^2-2 }\)

Answer 9

y=x2+6x-7x-y=1

Answer 10

\(\normalsize\color{blue}{ 6=9a-2 }\)
\(\normalsize\color{blue}{ 8=9a }\)
\(\normalsize\color{blue}{ a=8/9 }\)

So the parabola is: \(\normalsize\color{blue}{ y=\frac{\Large 8}{\Large9}(x+3)^2-2 }\)

Answer 11

I solved for a, using any of the points, knowing the vertex (-3,-2)

Answer 12

Will post it's graph.
\(\normalsize\color{blue}{ y=\frac{\Large 8}{\Large9}(x+3)^2-2 }\)

https://www.desmos.com/calculator/uh8o9n64da

Answer 13

found the parabola for you: \(\normalsize\color{blue}{ y=\frac{\Large 8}{\Large9}(x+3)^2-2 }\)

can you find the line for me?

Answer 14

i dont know how to

Answer 15

if you can't do it just from the graph,

have 2 points: \(\normalsize\color{blue}{ (-6,7) }\) and \(\normalsize\color{blue}{ (-1,2) }\)

use: \(\large\color{teal}{ m=\frac{\LARGE y_{\large 1}-y_{\large 2}}{\LARGE x_{\large 1}-x_{\large 2}} }\) for the slope.

Answer 16

still troubling

Answer 17

?

Answer 18

i got 8/-7

Answer 19

5/7

Answer 20

retry again please

Answer 21

remember when you subtract a negative it becomes a positive

Answer 22

\(\large\color{black}{ 7 -2 }\)
\(\large\color{black}{_{\Huge m= } ~~\text{__________} }\)
\(\large\color{black}{ -6 -(-1) }\)

Answer 23

so it would be 1

Answer 24

@SolomonZelman will using 3 points on the parabola and the equation ax^2 + bx = c = 0 take longer but give the same result?

Answer 25

no need

Answer 26

you want to find the prabaola, or what?

Answer 27

parabola*

Answer 28

for parabola, as I did:
\(\large\color{black}{ y=a(x+3)^2-2 }\) , because the vertex is given: \(\large\color{black}{ (-3,-2) }\)
and then plug in y-intercept \(\large\color{black}{ (0,6) }\) to solve for a.

(as I did, and got 8/9)

Answer 29

which seems to be perfect from the graph, https://www.desmos.com/calculator/und29v5sfy
\(\large\color{black}{ \smile }\)

Answer 30

y=x2-6x-7x-y=1

Answer 31

??

Answer 32

what have you found the line to be?
have you found the line or not?

Answer 33

no

Answer 34

you have the 2 points, we plugged them in,