Question

WILL GIVE A MEDAL

The graph of y = ax^2 + bx + c passes through the points (-2, 0), (0, -2), and (2, 0).

Determine the solution set of 0 = ax^2 + bx + c.

Answer 1

from the point (0,-2)

when x=0, y=-2

y = ax^2 + bx + c

let x = 0, so y=-2

-2 = 0 + 0 + c

c = -2

Answer 2

so far you have

y = ax^2 + bx -2

Answer 3

When x = +2 or x=-2, y=0, from the other 2 points

Answer 4

I thought the solution set was {0}

Answer 5

You plug in your points to find your constant value, then use that to find your roots, or x values.

Answer 6

{-2}, {0}, {-2,2}, and {-2,0,2} are the answer choices

Answer 7

(x-2) (x+2) will be factors of y=0

Answer 8

So.. what does that mean?

Answer 9

the solution set to
0 = ax^2 + bx + c

is where it crosses the x axis,, y = 0

Answer 10

it tells you the points in the problem, (2,0) and (-2,0)
those are the x-intercepts, y=0

Answer 11

So it would be the last one? {-2,0-2}

Answer 12

*{-2,0,2}

Answer 13

no, not zero, when x=0 y=-2 from the given point (0,-2)

Answer 14

you want the points where y=0, they are the solutions to

y = 0 = ax^2 + bx + c

Answer 15

{2 -2}

Answer 16

Why, thank you so much!

Answer 17

you're welcome, anytime

Answer 18

could find the actual values for a, b, and c, but not needed here, they tell you the x intercepts already

Answer 19

and a polynomial to the 2nd power degree, will have 2 intercepts