Need help finding the inverse.
\[f(x)= \frac{ x-5 }{ 3 }\] Find \[f ^{-1} (3)\]
@I_Always_Smiling @Taylev105
\(\large y = \frac{ x-5 }{ 3 } \) so \(\Large x = 3y + 5\) , let \(x=f^{-1} (t)\) so \(f^{-1} (t) = 3t + 5 \) and you can simply find \(\large f^{-1}(3) \)
Simply? I don't understand that. I done this lesson ages ago, I just don't remember what step to take with the given example first.
well,you know that the inverse of a function is that you write what does x equal to...suppose \( f(x) = y \) then you have \( \large y = \frac{ x-5 }{ 3 } \). you can find x from this equation,ok?
@Brostep0s
Right, so then I would add 5 the the y?
you have to find x from that equation,you can do anything but get the right answer : \( x = 3y + 5 \)
That's the equation I got, so then I would replace the y with an x right?
yes,let x a new function and then find what does \(f^{-1} \) equal to.
3. I got it, it's 14. Thanks a lot.
yes,you got the correct answer ;) , ur welcome
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