Question

@Michele_Laino

Answer 1

@Michele_Laino

Answer 2

I'm tying...

Answer 3

@iGreen

Don't spam! Common forms of spam include:
Posting a reply that is not relevant to the topic of discussion within that question.

-CoC

Answer 4

?? @AnswerMyQuestions

Answer 5

@AnswerMyQuestions You're spamming @kyley_bear Post and distracting her.

Answer 6

Please delete your comments, thank you. :P

Answer 7

from your text I read that motion f each two fireworks i uniform and vertical.
Now or fireworks A, we canwrite this:

Answer 8

\[h _{A}=v _{A}*t\]
and for firework B, we can write:
\[h _{B}=v _{B}*(t+\tau)\]

Answer 9

where tau=0.25 sec. Now the firework will explode when h_A=h_B, so when:
\[v _{A}*t=v _{B}*(t+\tau)\]

Answer 10

solving that above equation, for t, we have:
\[t=\frac{ v _{B} }{ (v _{A}-v _{B}) }*\tau \]

Answer 11

please insert your numerical data, and you will get your answer

Answer 12

sorry for my typo errors

Answer 13

.... I have no idea what all back slashes and B frac etc.

Answer 14

please note that, I think your answer is:
\[t+\tau =...\]

Answer 15

what is that do you not understand, please?

Answer 16

the equation. everything really all of it is greek to me.

Answer 17

from text of your problem, I have understood that the motion of each fireworks, is a uniform motion, and vertical, namely each firework is moving along a vertical line, with a constant speed
is it clear, please?

Answer 18

yeah.

Answer 19

perfect!

Answer 20

now, the equation of a uniform motion, namely the relationship among the speed, space and time elapsed, is:
\[z=v*t\]

Answer 21

namely space=speed times time
is it lear, please?

Answer 22

oops...is it clear, please?

Answer 23

yeah