if f(x) = 5x^3 - 2 and g(x) = x + 1 find (f-g) (x)
5x^4 - 2
5x^3 -x -3
5x^3 - x -1
5x^3 + 1

Question

if f(x) = 5x^3 - 2 and g(x) = x + 1 find (f-g) (x)
5x^4 - 2
5x^3 -x -3
5x^3 - x -1
5x^3 + 1

anonymous · Answer

Wouldn't (f-g)(x) = (5x^3-2)-(x+1)

michele_laino · Answer

please note that:
$$(f-g)(x)=f(x)-g(x)=...$$
so?

anonymous · Answer

$$(f-g) (x) $$ is simply $$f(x) - g(x)$$

anonymous · Answer

So, it would be (f-g)(x)=5x^3-2-x+1

michele_laino · Answer

please, be careful to signs! @GodGirl360

anonymous · Answer

Then my first equation that I set up would be correct, right @Michele_Laino. The next step would be to distribute the negative sign.
(f-g)(x)=5x^3-2-x-1
Then you would combine like terms.
(f-g)(x)=5x^3-x-3

anonymous · Answer

So, B is the answer?

michele_laino · Answer

please note that in your formula, namely:
(f-g)(x)=5x^3-2-x+1
there is a sign error, do you agree? @GodGirl360

anonymous · Answer

Yes, that is why I corrected myself and went back to  solving my initial equation, @Michele_Laino, which was (f-g)(x)=(5x^3-2)-(x+1). The rest of the work is mentioned in one of my last comments.

nnesha · Answer

@Tallan  did you understand ????

anonymous · Answer

So, would B be to answer?

anonymous · Answer

no im still a little confused on how you get it. So when you set the problem up (5x^3 - 2) - (x + 1) right? then you would distribute?

nnesha · Answer

yes

nnesha · Answer

let the asker solve this question **

anonymous · Answer

Sorry @Nnesha, got ahead of myself.

nnesha · Answer

please don't be sorry its okay

anonymous · Answer

ok so my question is which number do I use the 5x^3 to distribute?

nnesha · Answer

nope like she already mention above first post you have to subtract|dw:1420133123869:dw| distribute bracket by  -1