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3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l) Calculate the number of moles of water produced when 3.3 mol of Cu(NO3)2 are formed in the reaction A. 6.6 mol B. 8.8 mol C. 4.4 mol D. 4.9 mol
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4.4 moles of water will be produced 3.3 mole Cu x (4 moles water/3 moles Cu) = 4.4 moles water
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