Question

show that

Answer 1

:D use beta
\(\int_0^\infty\int_0^\infty\ e^{-(x+y)} x^{3}y^{4}\,\mathrm{d}x \,\mathrm{d}y.
\!\)=3!4!

Answer 2

or gamma

Answer 3

or anyhing else >.<

Answer 4

I got:
\[\Gamma(4)\Gamma(5)=4!*5!\]

Answer 5

damn! you're fast !!

Answer 6

sorry...3!*4!

Answer 7

haha yes

Answer 8

thank you all!

Answer 9

:D

Answer 10

\[\begin{align}\int_0^\infty\int_0^\infty\ e^{-(x+y)} x^{3}y^{4}\,\mathrm{d}x \,\mathrm{d}y &= \int_0^{\infty} e^{-x}x^3 dx \cdot \int_0^{\infty} e^{-y}y^4 dy \\~\\
&=\Gamma(4) \cdot \Gamma(5) \end{align}\]

Answer 11

pretty straightforward

Answer 12

hmm they should add thing to sketch tools

Answer 13

You're using contrast technique to show the brightness in eyes in all your drawings!
i notice that smiley face has two pupils/eyeballs and a missing nose :{