Visitors to a carnival can buy an unlimited-ride pass for $50 or an entrance-only pass for $20. In one day, 282 passes were sold for a total of $10,680. How many unlimited-ride passes were sold? (2 points)
Have you been provided with any further information?
YES GENERALLY YOU R GIVEN MORE INFORMATION
$50 unlimited-ride passes are going to be variable a $20 entrance-only passes are going to be variable b 282 passes were sold, so a + b = 282 $10,680 worth of passes were sold, so 50a + 20b = 10680
this is a system of equations problem. our equations being a + b = 282 50a + 20b = 10680
use the first equation and solve for b
Solve @AriPotta
once you do that, you can substitute that for b in the second equation and solve for a
a + b = 282 b = 282 - a 50a + 20b = 10680 50a + 20(282 - a) = 10680 solve for a and you'll have your answer
you decided to use subsitution method
yes, that seemed like the best way to go, in my opinion
I would have gone for multiplying by -20
well, it doesn't really matter. either way, you'll get your answer :P
lets go then
i want @tqosborne to get the answer for him/her self
-20 a -20b = -20(282) 50a + 20b = 10, 680
ok
its up to you @tqosborne
@AriPotta leave this one to you!
Sorry I was busy doing another problem. Thanks for the help guys :)
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