Question

@DanJS

Answer 1

i got f(x)= x^2+4x-8

Answer 2

@DanJS

Answer 3

here, sorry

Answer 4

its okay (: im pretty sure i did this right, i just want to double check

Answer 5

take a look here , this page explains it pretty good, http://mathmistakes.info/facts/CalculusFacts/learn/doi/doi.html

Answer 6

scroll down like half way

Answer 7

wait i just did it again and i got a diff answer,f(x)= x^2+4x-12

Answer 8

okk im looking

Answer 9

\[\frac{ d }{ dx} \int\limits_{0}^{x}(2t-4)dt = \frac{ d }{ dx }(t^2 -4t)_{0}^{x} = \frac{ d }{ dx }(x^2-4x) = 2x - 4\]

Answer 10

need 2 to x

Answer 11

so it would be -12 right?

Answer 12

yes?..

Answer 13

sorry, i cant remember what to do here

Answer 14

hahah its fine, thank you

Answer 15

this is calc 1 right?

Answer 16

yeah

Answer 17

its fine i got it(:

Answer 18

k, i havent done this in years, lol i would have to review